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In the event of an accidental decomposition, a solution of rare H2SO4 was taken and electricity was passed through it?​

Answer» <html><body><p><strong>Answer:</strong></p><p>Electrolysis of dilute sulphuric acid:-</p><p>At cathode-</p><p>2H </p><p>+</p><p> +<a href="https://interviewquestions.tuteehub.com/tag/2e-300683" style="font-weight:bold;" target="_blank" title="Click to know more about 2E">2E</a> </p><p>−</p><p> ⟶H </p><p>2</p><p> </p><p> </p><p></p><p>At anode-</p><p>4OH </p><p>−</p><p> +⟶2H </p><p>2</p><p> </p><p> O+2O </p><p>2</p><p> </p><p> +<a href="https://interviewquestions.tuteehub.com/tag/4e-318724" style="font-weight:bold;" target="_blank" title="Click to know more about 4E">4E</a> </p><p>−</p><p> </p><p></p><p>Overall reaction-</p><p>H </p><p>2</p><p> </p><p> O⟶2H </p><p>2</p><p> </p><p> +O </p><p>2</p><p> </p><p> </p><p></p><p>∴ <a href="https://interviewquestions.tuteehub.com/tag/amount-374803" style="font-weight:bold;" target="_blank" title="Click to know more about AMOUNT">AMOUNT</a> of substance liberated at cathode = 2 moles of H2</p><p></p><p> </p><p> =4g</p><p></p><p>Also, amount of substance liberated at anode = <a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> mole of O2</p><p></p><p> </p><p> =32g</p><p></p><p>∴ Ratio of the amount of substance liberated at the cathode and anode = 4</p><p><strong>Explanation:</strong></p><p>Mark as a brainliest answer</p></body></html>


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