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In the expansion of (xcosθ+1xsinθ)16, if l1 is the least value of the term independent of x when π8≤θ≤π4 and l2 is the least value of the term independent of x when π16≤θ≤π8, then the ratio l2:l1 is equal to : |
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Answer» In the expansion of (xcosθ+1xsinθ)16, if l1 is the least value of the term independent of x when π8≤θ≤π4 and l2 is the least value of the term independent of x when π16≤θ≤π8, then the ratio l2:l1 is equal to : |
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