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In the figure below ‘A’ shows a cell in the normal state and ‘B’ shows the same cell after leaving it in a certain solution for a few minutes.(i) Describe the change which has occurred in the cell as seen in B.(ii) Give the technical term for the condition of the cell as reached i n B and as it was in A.(iii) Define the process which led to this condition.(iv) What was the solution- isotonic, hypotonic or h ypertonic, in which the cell was kept ?(v) How can the cell in B, be brought back to its original condition ?(vi) Name the parts numbered 1 to 3. |
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Answer» (i) Exosmosis (exit of water ) has resulted in the shrinkage of the protoplasm of cell B. (ii) Plasmolysis and deplasmolysis. (iii) When plant cells are kept in a h ypertonic solution, exosmosis takes place. This process is called plasmolysis. (iv) Hyperton ic solution. (v) The cell in B can be b rought back to its original condition by placing it in a drop of distilled water. (vi) 1. Cell wall, 2. Plasma membrane, 3. Chloroplast. |
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