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In the given figure, ABCD, DCFE and ABFE are parallelogram. Show that ar(ΔADE) = ar(ΔBCF).

Answer» <html><body><p>given <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a>, ABCD, DCFE and ABFE are parallelogram. Show that ar(ΔADE) = ar(ΔBCF) Given:In the given figure, ABCD, DCFE and ABFE are parallelogram To find:Show that ar(ΔADE) = ar(ΔBCF) Solution:☃️ <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> ABCD a parallelogram, therefore <a href="https://interviewquestions.tuteehub.com/tag/sides-1207029" style="font-weight:bold;" target="_blank" title="Click to know more about SIDES">SIDES</a> AD and <a href="https://interviewquestions.tuteehub.com/tag/bc-389540" style="font-weight:bold;" target="_blank" title="Click to know more about BC">BC</a> are equal.☃️ Since, DCFE is also a parallelogram, therefore sides DE and FC are equal☃️ Since, ABFE is also a parallelogram, therefore sides AE and <a href="https://interviewquestions.tuteehub.com/tag/bf-390062" style="font-weight:bold;" target="_blank" title="Click to know more about BF">BF</a> are equal.So, ∆ ADE and ∆ BCF are congruent by S-S-S congruency rule. .°. Corresponding angles are equal in both trianglesHence, the areas will be equal.Therefore, ar(ΔADE) = ar(ΔBCF)_________________________</p></body></html>


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