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In the given figure, ABCD is a cyclic quadrilateral whose diagonals intersect at P such that ∠DBC = 60° and ∠BAC = 40°. Find(i) ∠BCD,(ii) ∠CAD. |
Answer» (i) We know that the angles in the same segment are equal So we get ∠BDC = ∠BAC = 40o Consider △ BCD Using the angle sum property ∠BCD + ∠BDC + ∠DBC = 180o By substituting the values ∠BCD + 40o + 60o = 180o On further calculation ∠BCD = 180o – 40o – 60o By subtraction ∠BCD = 180o – 100o So we get ∠BCD = 80o (ii) We know that the angles in the same segment are equal So we get ∠CAD = ∠CBD So ∠CAD = 60o |
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