1.

In the given figure, ABCD is a cyclic quadrilateral whose diagonals intersect at P such that ∠DBC = 60° and ∠BAC = 40°. Find(i) ∠BCD,(ii) ∠CAD.

Answer»

(i) We know that the angles in the same segment are equal

So we get

∠BDC = ∠BAC = 40o

Consider △ BCD

Using the angle sum property

∠BCD + ∠BDC + ∠DBC = 180o

By substituting the values

∠BCD + 40o + 60o = 180o

On further calculation

∠BCD = 180o – 40o – 60o

By subtraction

∠BCD = 180o – 100o

So we get

∠BCD = 80o

(ii) We know that the angles in the same segment are equal

So we get

∠CAD = ∠CBD

So ∠CAD = 60o



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