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In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD ≅ △BQC S2 : area(△APD) + area(PBCD) = area(△BQC) + area(CDPB) |
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Answer» In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD ≅ △BQC S2 : area(△APD) + area(PBCD) = area(△BQC) + area(CDPB) |
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