1.

In the given figure, ABCD is a parallelogram and PD is parallel to QC. S1 : △APD ≅ △BQC S2 : area(△APD) + area(PBCD) = area(△BQC) + area(CDPB)

Answer»

In the given figure, ABCD is a parallelogram and PD is parallel to QC.

S1 : APD BQC

S2 : area(APD) + area(PBCD) = area(BQC) + area(CDPB)




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