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In the given figure, ABCD is a square of side `14cm`.Semicircles are drawn with each side of square as diameter. Find the area of the shaded region. |
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Answer» Let `A_1` and `A_2` are area of the shaded and unshaded regions respectively. Let side of the square is `a` cm. Then, `A_1+A_2 = a^2->(1)`...[Area of square `= a^2` ] `Also, A_1/4+A_2/2 = pi/2(a/2)^2 = (pia^2)/8` `=>A_1+2A_2 = (pia^2)/2->(2)` From (1), `=>A_1+2(a^2-A_1) = (pia^2)/2` `=>A_1 = 2a^2-(pia^2)/2` `=>A_1 = a^2(2-pi/2)` `=>A_1 = (14)^2(2-22/(2*7))` ... [As `a = 14`] `A_1 = 196(3/7) = 84cm^2` So, required area is `84 cm^2`. |
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