1.

In the given figure, O is the centre of two concentric circles of radii 6 cm and 10 cm. AB is a chord of outer circle which touches the inner circle. The length of chord AB is(a) 8cm (b) 14 cm (c) 16 cm (d) √136 cm

Answer»

Correct answer is (c) 16 cm

We know that the radius and tangent are perpendicular at their point of contact In right triangle AOP

AO2 = OP2 + PA2

\(\Rightarrow\) 102 = 62 + PA2

\(\Rightarrow\) PA2 = 64

\(\Rightarrow\) PA = 8 cm

Since, the perpendicular drawn from the center bisect the chord

∴ PA = PB = 8 cm

Now, AB = AP + PB = 8 + 8 = 16 cm



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