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In the given figure, O is the centre of two concentric circles of radii 6 cm and 10 cm. AB is a chord of outer circle which touches the inner circle. The length of chord AB is(a) 8cm (b) 14 cm (c) 16 cm (d) √136 cm |
Answer» Correct answer is (c) 16 cm We know that the radius and tangent are perpendicular at their point of contact In right triangle AOP AO2 = OP2 + PA2 \(\Rightarrow\) 102 = 62 + PA2 \(\Rightarrow\) PA2 = 64 \(\Rightarrow\) PA = 8 cm Since, the perpendicular drawn from the center bisect the chord ∴ PA = PB = 8 cm Now, AB = AP + PB = 8 + 8 = 16 cm |
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