in the given progressive wave y = 5 sin (100 pi t -0.4 pi x) where yand x are in metre, t is in second. What is the (a) amplitude (b) wave length (c) frequency (d) wave velocity (e) particle velocity amplitude,

in the given progressive wave y = 5 sin (100 pi t -0.4 pi x) where ya

1.	in the given progressive wave y = 5 sin (100 pi t -0.4 pi x) where yand x are in metre, t is in second. What is the (a) amplitude (b) wave length (c) frequency (d) wave velocity (e) particle velocity amplitude,
Answer» <html><body><p></p>Solution :Comparing give equation, <br/> `y = 5 <a href="https://interviewquestions.tuteehub.com/tag/sin-1208945" style="font-weight:bold;" target="_blank" title="Click to know more about SIN">SIN</a> (100 pi t 0.4 pix)` <br/> with `y = a sin (omega t - kx + phi)` we get <br/> `a= 5m, k = 0.4pi =- (2pi)/(lamda ) implies lamda = 5m` <br/> `omega = 100 pi = 2pi f implies f = <a href="https://interviewquestions.tuteehub.com/tag/50-322056" style="font-weight:bold;" target="_blank" title="Click to know more about 50">50</a> Hz` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = (omega )/(k) = (100 pi)/(0.4pi) = <a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a> (m)/(s)` <br/> Maximum velocity of particle performing S.H.M. and taking part in the propagation of wave, <br/> `v _(max) = a omega` <br/> `= 5 xx 100 pi` <br/> `= <a href="https://interviewquestions.tuteehub.com/tag/500-323288" style="font-weight:bold;" target="_blank" title="Click to know more about 500">500</a> pi m//s`</body></html>