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In the previous problem, if `H_(1)` and `H_(2)` are the maximum heights in the two cases, thenA. `R = 2sqrt(H_(1)H_(2))`B. `R = 4sqrt(H_(1)H_(2))`C. `R = sqrt(H_(1)^(2) + H_(2)^(2))`D. `R = H_(1) - H_(2)` |
Answer» Correct Answer - B `theta: H_(1) = (u^(2) sin^(2) theta)/(2g)` `(90 - theta): H_(2) = (u^(2) sin^(2) (90 - theta))/(2g) = (u^(2) cos^(2) theta)/(2g)` `R = (u^(2))/(g).2 sin theta cos theta` `sqrt(H_(1)H_(2)) = sqrt((u^(2) sin^(2) theta)/(2g).(u^(2) cos^(2) theta)/(2g))` `= (u^(2) sin theta cos theta)/(2 g) = (1)/(4) ((u^(2))/(g).2 sin theta cos theta)` `= (1)/(4)R` `R = 4sqrt(H_(1)H_(2))` |
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