In the previous problem , the maximum loss in `K.E.` will beA. `(1)/(2) mv_(0)^(2)`B. `(1)/(3) mv_(0)^(2)`C. `(2)/(3) mv_(0)^(2)`D. `(3)/(4) mv_(0)^(2)`

In the previous problem , the maximum loss in `K.E.` will beA. `(1)/(2

1.	In the previous problem , the maximum loss in `K.E.` will beA. `(1)/(2) mv_(0)^(2)`B. `(1)/(3) mv_(0)^(2)`C. `(2)/(3) mv_(0)^(2)`D. `(3)/(4) mv_(0)^(2)`
Answer» Correct Answer - B For loss of `K.E`. to be maximum , the collision should be completely inelastic , i.e. the block should stick together and move with same velocity after the collision. `(Delta K)_(max) = (1)/(2) (m_(1) m_(2))/(m_(1) + m_(2)) (u_(1) - u_(2))^(2)` `= (1)/(2) ( m xx 2m)/( m + 2m) (v_(0) - 0)^(2)` `= (1)/(3) mv_(0)^(2)`

Discussion

No Comment Found

Related InterviewSolutions

Two paricle A and B initially at rest, move towards each other under mutual force of attraction. At the instant when the speed of A is V and the speed of B is 2V, the speed of the centre of mass of the system isA. zeroB. `v`C. `(3v)/(2)`D. `(3y)`
A paticle of mass `m` is executing uniform circular motion on a path of radius `r`. If `p` is the magnitude of its linear momentum, then the radial force acting on the particle isA. `p m r`B. `r m//p`C. `m p^(2)//r`D. `p^(2) //r m`
A body falling from a height of `10 m` rebounds from the hard floor . ItA. `0.89`B. `0.56`C. `0.23`D. `0.18`
The rate of mass of the gas emitted from the rear of a rocket is initially `0.1 kg//s`. If the speed of the gas relative to the rocket is `50 m//s` and the mass of the rocket is `2 kg` , then the acceleration of the rocket in `m//s^(2)` isA. `5`B. `5.2`C. `2.5`D. `25`
Which of the following is true for center of mass ? (i) The center of mass of a body may lie within , outside , on the surface of the body. (ii) In the case of symmetrical bodies , the center of mass coincides with the geometrical center of the body. (iii) In the absence of external forces , the center of mass moves with constant velocity. (iv) If external forces are absent and system is initially at rest, then location of center of mass is fixed.A. `(i) ,(ii)`B. `(i) ,(ii) ,(ii)`C. `(ii) ,(iii) ,(iv)`D. all options are correct
Two balls are thrown simultaneously from top of tower in air as shown in the figure. (i) The acceleration of the center of mass of two balls while in air is equal to `g`. (ii) The path followed by the center of mass is parabola. (iii) The path followed by the center of mass will change if one ball after striking the ground comes to rest. A. `(i),(ii) ,(iii)`B. `(i),(ii) ,(iv)`C. `(i),(ii)`D. all of the above
Two blocks of mass `1kg` and `3 kg` have position v ectors ` hat(i) + 2 hat(j) + hat(k)` and `3 hat(i) - 2 hat(j) + hat(k)` , respectively . The center of mass of this system has a position vector.A. `- 2 hat(i) + 2 hat(k)`B. `-2 hat(i) - hat(j) + hat(k)`C. `2.5 hat(i) - hat(j) - hat(k)`D. `- hat(i) + hat(j) + hat(k)`
The force `F` acting on a partical of mass `m` is indicated by the force-time graph shown below. The change in momentum of the particle over time interval from zero to 8 `s` is. A. `20 Ns`B. `12 Ns`C. `6 Ns`D. `24 Ns`
A cubical block of ice of maas m and edge L is placed in a large tray of maas M. If the ie melts, how far does the centre of maas of the system 'ice plus tray' come down?A. `(mL)/((m + M))`B. `(mL)/(2(m + M))`C. `(mL)/(M)`D. `(ML)/(m)`
A ball hits the floor and rebounds after an inelastic collision. In this caseA. `(i) ,(ii)`B. `(i) ,(iv)`C. `(ii) ,(iii)`D. `(iii) ,(iv)`

In the previous problem , the maximum loss in `K.E.` will beA. `(1)/(2) mv_(0)^(2)`B. `(1)/(3) mv_(0)^(2)`C. `(2)/(3) mv_(0)^(2)`D. `(3)/(4) mv_(0)^(2)`

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment