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In the question number 36, at which distance a weight may be hung along the rod, in order to produce equal strains in both the wires?

Answer» <html><body><p>`(4)/(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)m`from steel wire<br/>`(4)/(3)m`from brass wire<br/>1 m from steel wire <br/>`(1)/(4)m`from brass wire</p>Solution :As Strain `= ("Srtress")/("Young's Modulus")` <a href="https://interviewquestions.tuteehub.com/tag/ltbr-2804405" style="font-weight:bold;" target="_blank" title="Click to know more about LTBR">LTBR</a> `therefore` Strainin stell wire `= (T_(S))/(A_(S)Y_(S))` <br/>For equal strain in both the wire,<br/> `(T_(S))/(A_(S)Y_(S)) = (T_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>))/(A_(B)Y_(B))`<br/> `therefore (T_(S))/(T_(B))=(A_(S))/(A_(B)) (Y_(S))/(Y_(B)) = (0.1 cm^(2))/(0.2 cm^(2)) xx (2xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>)N m^(-2))/(1 xx 10^(11) N m^(-2))= 1 .......(i)` <br/> For therotational equlibrium of the rod, <br/> `T_(S)x = T_(B) (2-x)` <br/>`(2-x)/(x) = (T_(S))/(T_(B))= 1""["Using (i)"]` <br/> `2 - x = x or x=1m `</body></html>


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