In the question number 52, the speed with which the stone hits the gro

1.	In the question number 52, the speed with which the stone hits the ground is
Answer» 15 m `s^(-1)` 90 m `s^(-1)` 99 m `s^(-1)` 49 m `s^(-1)` SOLUTION :Motion along horizontal DIRECTION, `downarrow +ve` `u_(x) = 15 ms^(-1), a_(x) = 0` `v_(x) = u_(x) + a_(x)t = 15 + 0 xx 10 = 15 ms^(-1)` Motion along vertical direction, `u_(y) = 0, a_(y) = G` `v_(y) = u_(y) + a_(y)t = 0 + 9.8 xx 10 = 98 ms^(-1)` `THEREFORE` Speed of the stone when it hits the ground is `v = sqrt(v_(x)^(2) + v_(y)^(2)) = sqrt((15)^(2) + (98)^(2)) ~~ 99 ms^(-1)`

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