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In the question number 97, time taken by the child to go from father to mother and back to father is

Answer» <html><body><p>10 s<br/>20 s<br/>30 s<br/>40 s</p>Solution :Distance between the <a href="https://interviewquestions.tuteehub.com/tag/parents-1147056" style="font-weight:bold;" target="_blank" title="Click to know more about PARENTS">PARENTS</a> = 50 m <br/> Since the parents and child are located on the same <a href="https://interviewquestions.tuteehub.com/tag/belt-895014" style="font-weight:bold;" target="_blank" title="Click to know more about BELT">BELT</a>, the <a href="https://interviewquestions.tuteehub.com/tag/speed-1221896" style="font-weight:bold;" target="_blank" title="Click to know more about SPEED">SPEED</a> of the child as observed by the stationary <a href="https://interviewquestions.tuteehub.com/tag/observer-1127626" style="font-weight:bold;" target="_blank" title="Click to know more about OBSERVER">OBSERVER</a> in either <a href="https://interviewquestions.tuteehub.com/tag/direction-1696" style="font-weight:bold;" target="_blank" title="Click to know more about DIRECTION">DIRECTION</a> (either from mother to father or from father to mother) will be `9 km h^(-1)(= 5/2 m s^(-1))`. <br/> `therfore` Time taken by the child to go father to mother and back to father is <br/> `t = 50/(5/2) + 50/(5/2) = 20 s + 20 s = 40` s.</body></html>


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