In the reaction, `FeS_(2)+KMnO_(4)+H^(+) to Fe^(3+)+SO_(2)+Mn^(2+)+H_(2)O` the equivalent mass of `FeS_(2)` would be equal to :A. molar massB. `("molar mass")/(10)`C. `("molar mass")/(11)`D. `("molar mass")/(13)`

In the reaction, `FeS_(2)+KMnO_(4)+H^(+) to Fe^(3+)+SO_(2)+Mn^(2+)+H_(

1.	In the reaction, `FeS_(2)+KMnO_(4)+H^(+) to Fe^(3+)+SO_(2)+Mn^(2+)+H_(2)O` the equivalent mass of `FeS_(2)` would be equal to :A. molar massB. `("molar mass")/(10)`C. `("molar mass")/(11)`D. `("molar mass")/(13)`
Answer» Correct Answer - C `Fe^(2+) to Fe^(3+) + e^(-), S_(2)^(2-) to 2S^(4+)+10e^(-)` `therefore FeS_(2) to 2S^(4+)+Fe^(3+)+11e^(-)` Equivalent mass of `FeS_(2) =("Molar mass")/(11)`

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In the reaction, `FeS_(2)+KMnO_(4)+H^(+) to Fe^(3+)+SO_(2)+Mn^(2+)+H_(2)O` the equivalent mass of `FeS_(2)` would be equal to :A. molar massB. `("molar mass")/(10)`C. `("molar mass")/(11)`D. `("molar mass")/(13)`

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