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In the reaction `Zn(s) + 2H^(+)(aq.) rarr Zn^(2+)(aq.) + H_(2) (g)`, how many liters of hydrogen gas measured at `STP` is produced when `6.54g` of `Zn` is used `(Zn = 65.4 u)` ?A. `22.4 L`B. `11.2 L`C. `2.24 L`D. `1.12 L` |
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Answer» Correct Answer - C According to the equation, 1 mol `Zn` releases 1 mol `H_(2)`. Thus, `n_(H_(2)) = n_(Zn) = (6.54g)/(65.4g) = 0.1 mol` Which occupies `2.24 L` at `STP`. |
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