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In which of the following cases `(E_(cell)-E_(cell)^(@))` is zero :A. `Cu|Cu^(2+)(0.01 M)||Ag^(+)(0.1 M)|Ag`B. `Pt(H_(2))|pH=1||Zn^(2+)(0.01 M)|Zn`C. `Pt(H_(2))|pH=1||Zn^(2+)(1 M)|Zn`D. `Pt(H_(2))|H^(+)=0.01 M)||Zn^(2+)(0.01 M)|Zn` |
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Answer» Correct Answer - A::B (a,b) are correct. (a) `E_(cell)=E_(cell)^(@)-(2.303" RT")/(2F)"log"([Cu^(2+)])/([Ag^(+)]^(2))` `E_(cell)-E_(cell)^(@)=(2.303" RT")/(2F)"log"(0.01)/((0.1)^(2))` `E_(cell)-E_(cell)^(@)=0` (b) `E_(cell)-E_(cell)^(@)=-(2.303" RT")/(2F)"log"([H^(+)]^(2))/([Zn^(2+)])` `E_(cell)-E_(cell)^(@)=-(2.303" RT")/(2F)"log"((1xx10^(-1))^(2))/((0.01))=0` (c ) `E_(cell)-E_(cell)^(@)=-(2.303" RT")/(2F)"log"([H^(+)]^(2))/([Zn^(2+)])` `=-(2.3030" RT")/(2F)"log"((1xx10^(-1))^(2))/(1)ne 0` (d) `E_(cell)-E_(cell)^(@)=-(2.303" RT")/(2F)"log"([H^(+)]^(2))/([Zn^(2+)])` `=-(2.303" RT")/(2F)"log"((0.1)^(2))/((0.01))ne0` |
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