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`int(dx)/(x(x^n+1))` is equal toA. `(1)/(n)log((x^(n))/(x^(n)+1))+c`B. `(1)/(n)log((x^(n)+1)/(x^(n)))+c`C. `log((x^(n))/(x^(n)+1))+c`D. non of these |
Answer» Correct Answer - A `I=int(dx)/(x(x^(n)+1))=int(x^(n-1))/(x^(n)(x^(n)+1))dx` `"Putting " x^(n)=t " so that " nx^(n-1)dx=dt, i.e.,` ` "we get " x^(n-1)dx=(1)/(n)dt` `I=int((1)/(n)dt)/(t(t+1))=(1)/(n)int((1)/(t)-(1)/(t+1))dt` `=(1)/(n)(log t-log(t+1))+C` `=(1)/(n)log((x^(n))/(x^(n)+1))+C` |
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