`int (" In" x)^(-1) dx - int ("In" x)^(-2) dx` is equal toA. `x ("In " x)^(-1) + c`B. `x("In " x)^(-2) + c`C. `x(" In "x) +c`D. `x("In " x)^(2) + c`

`int (" In" x)^(-1) dx - int ("In" x)^(-2) dx` is equal toA. `x ("In "

1.	`int (" In" x)^(-1) dx - int ("In" x)^(-2) dx` is equal toA. `x ("In " x)^(-1) + c`B. `x("In " x)^(-2) + c`C. `x(" In "x) +c`D. `x("In " x)^(2) + c`
Answer» Correct Answer - A `int (l nx)^(-1) dx - int (l n x)^(-2) dx` `= int [(1)/(l nx) - (1)/((l nx)^(2))].dx` Put `l nx = t rArr x = e^(t)` `dx = e^(t).dt` `:. int [(1)/(l nx) - (1)/((l nx)^(2))] dx = int ((1)/(t) - (1)/(t^(2))) .e^(t).dt` `= int e^(t) .((1)/(t) - (1)/(t^(2))) .dt` `= (e^(t))/(t) + c = (x)/(l nx) + c` `= x(l nx)^(-1) + c`

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`int (" In" x)^(-1) dx - int ("In" x)^(-2) dx` is equal toA. `x ("In " x)^(-1) + c`B. `x("In " x)^(-2) + c`C. `x(" In "x) +c`D. `x("In " x)^(2) + c`

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