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Iron changes its crystal structure from body-centred to cubic close- packed structure when heated to ` 916^(@)C`. Calculate the ratio of the density of the bcc crystal to that of ccp crystal, assuming that the metallic radius of the atom does not change. |
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Answer» In the bcc packing, the space occupied is 68% of the total volume available while in ccp, the space occupied is 74% . This means that for the same volume, masses of bcc and ccp are in the ratio of 68 : 74 . As the volume is same , ratio of density is also same, viz , 68 : 74 . i.e,x ` (d(ccp))/(d(ccp)) = 68/74 = 0.919` Alternatively Density ` (p) = (Z xx M)/( a^(3) xx N_(0))` For bcc, ` Z = 2, r= ( sqrt3 a)/4 or a_("bcc") = (4r)/sqrt3` For fcc, ` Z = 4 , r = a/(2sqrt2) or a_("fcc") = 2 sqrt2 r ` ` p_("bcc")= (2xxM)/((a_("bcc"))^(3) xx N_(0)) and p_("fcc") = ( 4 xx M)/((a_("fcc"))^(3)xx N_(0))` `p_("bcc")/(P_("fcc"))= 2/((a_("bcc"))^(3))xx ((a_("fcc"))^(3))/4 = 2/((4r//sqrt3)^(3))xx ((2sqrt2r)^(3))/4 = (2xx3sqrt3)/(64 r^(3)) xx (16sqrt2 r^(3))/4 = 3/8sqrt6 = 0.919` |
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