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InterviewSolution
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its first (m + n) terms is zero.10. The perimeter of a right triangle is 60 cm. Its hypotenuse is 25 cm. Find the area of the triangle. |
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Answer» Perimeter of that triangle = 60cm the measure of hypotaneous = 25cm then the rest sides must measure = 60-25= 35 let one side be xthen, thw measure of the third side must be 35 - xusing pythagoras theorem (25)^2 =(x)^2 + (35-x)^2625 = x^2 + x^2 - 70x + 1225 x^2 + x^2 - 70x + 1225 = 625x^2 + x^2 - 70x + 1225 -625 = 02 x^2 - 70x + 600 = 02x^2 - 40x - 30 x + 600= 02x (x-20) -30 ( x - 20) = 0(x-20)(2x-30)=0x -20 = 0x = 20 2x -30 =02x =30x = 15so,one of the side measure either 20 cm 15 cmif one side measure 20cm then the other must measure 35 -20 = 15cmand if it measured 15 cm then the other side measure 35-15 = 20 cmso,we will get 20cm and 15 cm as our remaining sides. one of then will be height and the other misy be the base,now apply the formula of area of triangle i.e (1/2) (height)(base)= (1/2 )(20)(15) = 150 cm^2so, the area of that triangle will be 150 cm^2. |
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