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Justify that the reaction : 2Cu_(2) O(s) + Cu_(2)S (s) rarr 6 Cu (s) + SO_(2) (g) is a redox reaction. Identify the species oxidised/reduced, which acts as an oxidant and which acts as a reductant.

Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(+1)(2Cu_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))overset(-2)(O_((s)))+overset(+1)(Cu_(2))overset(-2)(S_((s)))rarroverset(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)(6Cu_((s)))+overset(+4-2)(SO_(2))` <br/> In this reaction copper is reduced from `+ 1` state to zero oxidation state and <a href="https://interviewquestions.tuteehub.com/tag/sulphur-1234343" style="font-weight:bold;" target="_blank" title="Click to know more about SULPHUR">SULPHUR</a> is oxidised from `- 2` state to `+ 4` state. The above reaction is thus a redox reaction. <br/> Further, `Cu_(2)S` helps sulphur in `Cu_(2)S` to <a href="https://interviewquestions.tuteehub.com/tag/increase-1040383" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASE">INCREASE</a> its oxidation number,therefore `Cu(I)` is an oxidant, and sulphur of `Cu_(2)S` helps copper both in `Cu_(2)S` itself and `Cu_(2)O` to decrease its oxidation number, therefore, sulphur of `Cu_(2)S` is reductant.</body></html>


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