InterviewSolution
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InterviewSolution
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`K_(2)SO_(4)` solution mixed with `Cr_(2)(SO_(4))_(3)` solution in 1:1 molar ratio gives the test of `Cr^(3+)` ion but `CuSO_(4)` solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of `Cu^(2+)` ion. Explain why ? |
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Answer» `K_(2)SO_(4).Cr_(2)(SO_(4))_(3) overset(aq)iff2K^(+)(aq)+2Cr^(3+)(aq)+4SO_(4)^(2-)` So chrome alum is double salt. It when dissolved in water gives its constituent ions. Hence it gives the test of `K^(+),Cr^(3+) and SO_(4)^(2-)` ions. `CuSO_(4).4NH_(3)[Cu(NH_(3))_(4)SO_(4) overset(aq)iff[Cu(NH_(3))_(4)]^(2+)(aq)+SO_(4)^(2-)(aq)` As copper (II) is present in coordination sphere it will not given the test of `Cu^(2+)` ion. |
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