KBr (potassium bromide) contains 32.9% by weight of potassium. IF 6.40

1.	KBr (potassium bromide) contains 32.9% by weight of potassium. IF 6.40 g of bromine reacts with 3.60 g of potassium, calculate the number of moles of potassium which combine with bromine to from KBr
Answer» Answer: Explanation: For 100 gm of KBr sample, mass of K = 32.9 gm Mass of Br = 100 -32.9 = 67.1 So, if 67.1 gm of bromine REACTS with 32.9 gm of potassium Then 6.40 gm Br will react with = (32.9/67.1) x 6.40 = 3.14 gm potassium. So, in the given sample the amount of potassium which will be un reacted is = 3.60 -3.14 = 0.46 gm Now, as we know that, mass of potassium reacting in the KBr sample = 3.14 gm So, MOLES of potassium = given mass/ MOLAR mass = 3.14/ 39 = 0.08 moles. Hence, 0.08 moles of potassium combines to form KBr .

KBr (potassium bromide) contains 32.9% by weight of potassium. IF 6.40 g of bromine reacts with 3.60 g of potassium, calculate the number of moles of potassium which combine with bromine to from KBr

Answer»

Answer:

Explanation:

For 100 gm of KBr sample, mass of K = 32.9 gm

Mass of Br = 100 -32.9 = 67.1

So, if 67.1 gm of bromine REACTS with 32.9 gm of potassium

Then 6.40 gm Br will react with = (32.9/67.1) x 6.40 = 3.14 gm potassium.

So, in the given sample the amount of potassium which will be un reacted is = 3.60 -3.14 = 0.46 gm

Now, as we know that, mass of potassium reacting in the KBr sample = 3.14 gm

So, MOLES of potassium = given mass/ MOLAR mass = 3.14/ 39 = 0.08 moles.

Hence, 0.08 moles of potassium combines to form KBr .