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Keeping the volume constant, the pressure of the gas is increased by 10% of its original value by increasing the temperature from 27^(0) C. Find the final temperature. |
Answer» <html><body><p></p>Solution :Initial <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> of the gas `(P_(1)) = P ` <br/> Final pressure of the gas `(P_(2)) = (110)/(100)` P <br/> Initial temperature `t_(1)^(0) <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = 27^(0)` C <br/> `T_(1) = 27 + <a href="https://interviewquestions.tuteehub.com/tag/273-1832932" style="font-weight:bold;" target="_blank" title="Click to know more about 273">273</a> = 300` K <br/> Final temperature `t_(2)^(0) C `= ? <br/> At constant volume, according to Charles law `(P_(1))/(T_(1)) = (P_(2))/(T_(2))` <br/> `T_(2) = (P_(2))/(P_(1)) T_(1) = (110P//100)/(P) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 300 = 330` <br/> `t_(2) = 330 - 273 = 57^(0)` C</body></html> | |