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Kenitic energy derivation |
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Answer» May this help you toooo 1.Let us consider a body of mass \'m\' placed on frictoinless surface.2.Let initial velocity be \'u\' & final velocity be \'v\'.3.By applying force \'f\' body gets displaced at distance \'s\'4.Now according to Newton 2 law of motion :- F=ma5.Now according to uniformaccelarated motion : V2-U2=2as V2-U2/2a=s6.Now according to defination of work done W=ma×v2-u2/2a W=1/2m(v2-u2)But here workdone is due to motion of the body hence w=EkEk=1/2m(v2-u2)If initial velocity is zero i.e.u=0 Ek =1/2mv2 W=fsV2 - u2= 2as, s=v2 /va F=ma, w=ma, v2/2aW=KE=mv2/2=1/2 mv2Hope it will help you? |
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