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Let a, b, c, d, e, f, g be consecutive even numbers and j, k, l, m, n be consecutive odd numbers. What is the average of all the numbers?1). 3(a + n)/22). (5l + 7d)/43). (a + b + m + n)/44). None of the above |
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Answer» Since a, b, c, d, e, f, g be consecutive even numbers; Suppose a = 2, b = 4, c = 6, d = 8, e = 10, f = 12 and g = 14. Since j, K, l, m, n be consecutive odd numbers; Suppose j = 1, k = 3, l = 5, m = 7 and n = 9. ∴ Average of all the numbers = (a + b + c + d + e + f + g + j + k + l + m + n)/12 Putting the values of every term as SUPPOSED above; ∴ Average of all the numbers = (56 + 25)/12 = 81/12 = 27/4 On checking with the options, any OPTION will not be satisfied with this data. ∴ NONE of the above |
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