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Let ABCD be a parallelogram whose diagonals intersect at P and O be the origin, then OA+OB+OC+OD equals |
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Answer» SOLUTION :Since, thediagonals of a paralelogram bisect each other. Therefore, P is the middle point of AC and BD both. `:.""OA + OC = 2 OP" and "OB+OD=2OP` `rArr""OA+OB+OC+OD=4 OP` |
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