1.

Let ABCD be a parallelogram whose diagonals intersect at P and O be the origin, then OA+OB+OC+OD equals

Answer»

`OP`
`2 OP`
`3 OP`
`4 OP`

SOLUTION :Since, thediagonals of a paralelogram bisect each other. Therefore, P is the middle point of AC and BD both.
`:.""OA + OC = 2 OP" and "OB+OD=2OP`
`rArr""OA+OB+OC+OD=4 OP`


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