1.

Let alpha != beta satisfy alpha^(2)+1=6alpha, beta^(2)+=6beta . Then, the quadraticequation whose roots are (alpha)/(alpha+1),(beta)/(beta+1) is

Answer»

`8X^(2)+8x+1=0`
`8x^(2)-8x-1=0`
`8x^(2)+8x+1=0`
`8x^(2)+8x-1=0`

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