Let `barv,v_(rms) and v_p` respectively denote the mean speed. Root mean square speed, and most probable speed of the molecules in an ideal monatomic gas at absolute temperature T. The mass of a molecule is m. ThenA. no molecules can have a speed greater than `sqrt2v_(rms)`B. no molecule can have a speed less than `v_p//sqrt2`C. `v_p lt barv lt v_(rms)`D. the average kinetic energy of a molecules is `3/4mv_p^2`.

Let `barv,v_(rms) and v_p` respectively denote the mean speed. Root me

1.	Let `barv,v_(rms) and v_p` respectively denote the mean speed. Root mean square speed, and most probable speed of the molecules in an ideal monatomic gas at absolute temperature T. The mass of a molecule is m. ThenA. no molecules can have a speed greater than `sqrt2v_(rms)`B. no molecule can have a speed less than `v_p//sqrt2`C. `v_p lt barv lt v_(rms)`D. the average kinetic energy of a molecules is `3/4mv_p^2`.
Answer» Correct Answer - C::D (c,d) We know that `barv=sqrt((8RT)/(piM)),v_(rms)=sqrt((3RT)/M) and `v_p=sqrt((2RT)/M)` From these expressions, we can conclude that `v_pltbarvltv_(rms)` Also the average kinetic energy of gaseous molecule is `barE=1/2mv_(rms)^2=1/2m(3/2v_p^2)=3/4mv_p^2`

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