1.

Let C be a curve which is locus of the point of the intersection of lines x = 2 + m and my = 4 – m. A circle (x – 2)2 + (y + 1)2 = 25 intersects the curve C at four points P, Q, R and S. If O is the centre of curve ‘C’ than OP2 + OQ2 + OR2 + OS2 is(a)  25(b)  50(c)   25/2(d)  100

Answer»

Correct option  (d)  100

Explanation:

x – 2 = m

y + 1 = 4/m

(x–2)(y+1) = 4

XY = 4, where X = x – 2 and Y = y + 1

and (x – 2)2 + (y + 1)2 = 25

X2 + Y2 = 25

 Curve C and circle both are concentric.

∴ OP+ OQ+ OR+ OS2 = 4r2

= 4 (25) = 100 



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