InterviewSolution
Saved Bookmarks
| 1. |
Let C be a curve which is locus of the point of the intersection of lines x = 2 + m and my = 4 – m. A circle (x – 2)2 + (y + 1)2 = 25 intersects the curve C at four points P, Q, R and S. If O is the centre of curve ‘C’ than OP2 + OQ2 + OR2 + OS2 is(a) 25(b) 50(c) 25/2(d) 100 |
|
Answer» Correct option (d) 100 Explanation: x – 2 = m y + 1 = 4/m (x–2)(y+1) = 4 XY = 4, where X = x – 2 and Y = y + 1 and (x – 2)2 + (y + 1)2 = 25 X2 + Y2 = 25 Curve C and circle both are concentric. ∴ OP2 + OQ2 + OR2 + OS2 = 4r2 = 4 (25) = 100 |
|