1.

Let f, g, and h be functions from R to R. Show that (f + g) o h = foh + goh

Answer»

Solution :[ (F + g) o H ] (x) = (f + g) (h(x))
=f(h(x)) + g (h(x))
(f o h) (x) + (g o h) (x))
(FOH + GOH) (x), for all `x in R`
Thus, (f + g) o h = f o h + g o h


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