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Let ` f : R to R` be a function given by `f(x+y) = f(x) + f(y) ` for all x,y `in`R such that `f(1)= a` Then, `f (x)=`A. `a^(x)`B. `ax`C. `a^(x)`D. `a+x` |
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Answer» Correct Answer - B We know that the general formula for the function `f: R to R ` given by `f (x)f(y)` for all x,y `in`R `f(x) = xf(1) rArr f (x) =ax" "[because f(1) =a]` |
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