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Let f: R to R be defined as f(x) = x^(4) . Choose the correct answer. |
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Answer» `f` is one-one onto Let `x, y in R and f(x) = f(y)` `rArr "" x^(4) = y^(4) rArr x = pm y` `thereforef` is not one-one. `rArr f` is many one. Again let `f(x) =y ` where `y in R` `rArr "" x^(4) = y ` `rArr "" x= (y)^(1//4)notin R if y = -1 ` `therefore f ` is not onto. Therefore, `f` is neither one-one nor onto. |
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