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Let f(x)=a_(0)+a_(1)x+a_(2)x^(2)+……+a_(2n)x^(2n) and g(x)=b_(0)+b_(1)x+b_(2)x^(2)+….+b_(n-1)x^(n-1)+x^(n)+x^(n-1)+….x^(2n). If f(x)=g(x+1), then a_(n) in terms of n is equal to : |
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Answer» `""^(2n+1)C_(n+1)` |
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