Let f(x)=f1(x)−2f2(x),where, f1(x)={min{x2, |x|}, |x|≤1 max{x2, |x|}, |x|>1 and, f2(x)={min{x2, |x|}, |x|>1 max{x2, |x|}, |x|≤1 and, g(x)={min{f(t): −3≤t≤x, −3≤x<0}max{f(t): 0≤t≤x, 0≤x≤3}For x∈(−1,0), f(x)+g(x) is

Let f(x)=f1(x)−2f2(x),where, f1(x)={min{x2, |x|}, |x|≤1 max{x2, |x

1.	Let f(x)=f1(x)−2f2(x),where, f1(x)={min{x2, \|x\|}, \|x\|≤1 max{x2, \|x\|}, \|x\|>1 and, f2(x)={min{x2, \|x\|}, \|x\|>1 max{x2, \|x\|}, \|x\|≤1 and, g(x)={min{f(t): −3≤t≤x, −3≤x<0}max{f(t): 0≤t≤x, 0≤x≤3}For x∈(−1,0), f(x)+g(x) is
Answer» Let $f (x) = f_{1} (x) - 2 f_{2} (x)$ , where, $f_{1} (x) = {\begin{matrix} min {x^{2}, \| x \|}, & \| x \| \leq 1 max {x^{2}, \| x \|}, & \| x \| > 1 \end{matrix}$ and, $f_{2} (x) = {\begin{matrix} min {x^{2}, \| x \|}, & \| x \| > 1 max {x^{2}, \| x \|}, & \| x \| \leq 1 \end{matrix}$ and, $g (x) = {\begin{matrix} min {f (t) : - 3 \leq t \leq x, - 3 \leq x < 0} max {f (t) : 0 \leq t \leq x, 0 \leq x \leq 3} \end{matrix}$ For $x \in (- 1, 0)$ , $f (x) + g (x)$ is