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Let f(X)=In (2x -x^2)+ sin (pix)/(2). Then which one of the following options is not correct? |
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Answer» Also `f(1+alpha)=f(1-alpha)for all alpha in (0,1)` So ,y =f (x) is symmetircal about the line x=1 Clearly `2 x-x^2` and SIN `(pix)/(2)` attain the maximum value 1 at x=1 Therefore `f(x)=In(2x-x^2)+sin (pix)/(2)` attains its maximum value at x=1 .Also We OBSERVE that `f(x) rArr - oo as x rArr 0^(+) or x rArr2^(-)` minmum values of the function f(x) does not EXIST HENCE ,option (b) is not correct |
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