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Let (hatp xx vecq) xx (hatp.vecq)vecq =(x^(2)+y^(2))vecq + (14-4x-6y)vecp Where hatp and hatq are two non-collinear vectors vecp is unit vector and x,y are scalars. Then the value of (x+y) is |
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Answer» 4 `rArr (hatp.hatp)vecq+(1-4x-6y)hatp` Since `hatp` and `vecq` are non-zero non-collinear. We can COMPARE coefficients of vectors `hatp` and `hatq`. `therefore 1+hatp.vecq=x^(2)+y^(2)`.............(i) And `hatp.vecq=4x+6y-14`............(II) From (i) and (ii), we get `rArr x^(2) + y^(2)-4x-6y+13=0` `rArr (x-2)^(2)+(y-3)^(2)=0` x=2 and y=3 |
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