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`"Let " k(x)=int((x^(2)+1)dx)/(root(3)(x^(3)+3x+6)) " and " k(-1)=(1)/(root(3)(2)). " Then the value of " k(-2) " is "-.` |
Answer» Correct Answer - 2 `k(x)=int((x^(2)+1)dx)/((x^(3)+3x+6)^(1//3))` `"Put " x^(3)+3x+6=t^(3)` `"or " 3(x^(2)+1)dx=3t^(2)dt` `k(x)=int(t^(2)dt)/(t)=(t^(2))/(2)+C=(1)/(2)(x^(3)+3x+6)^(2//3)+C` `k(-1)=(1)/(2)(2)^(2//3)+C " or " C=0` ` :. k(x)=(1)/(2)(x^(3)+3x+6)^(2//3),f(-2)=(1)/(2)(-8)^(2//3)` `=(1)/(2)[(-2)^(3)]^(2//3)=2` |
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