Let `n_1

1.	Let `n_1
Answer» Correct Answer - 7 If `n_(1),n_(2),n_(3),n_(4)` take minimum values 1,2,3,4 respectively, then `n_(5)` will be maximum 10. `therefore`corresponding to `n_(5)=10` there is only one solution `n_(1)=1,n_(2)=2,n_(3)=3,n_(4)=4` Corresponnding to `n_(5)=9`, we can have, `n_(1)=1,n_(2)=2,n_(3)=3,n_(4)=5` i.e., one solution Corresponding to `n_(5)=8`, we have, `n_(1)=1,n_(2)=2,n_(3)=3,n_(4)=6` or `n_(1)=1,n_(2)=2,n_(3)=4,n_(4)=5` i.e., two solutions corresponding to `n_(5)=5`, we can have `n_(1)=1,n_(2)=2,n_(3)=4, n_(4)=6` or `n_(1)=1,n_(2)=3,n_(3)=4,n_(4)=5` i.e., two solutions Corresponding to `n_(5)=6` we can have `n_(1)=2,n_(2)=3,n_(3)=4,n_(4)=5` i.e., one solution thus, there can be 7 solutions.

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