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Let N be the least positive integer such that whenever a non-zero digit c is written after the last digit of N, the resulting number is divisible by c. The sum of the digits of N is(a) 9(b) 18(c) 27(d) 36 |
Answer» Answer is : (a) 9 As N be the least positive integer and when a non-zero digit C is written after the last digit of N, the resulting number is divisible by C. So, 10N + C is divisible by C. ∴10 N must be divisible by C. Now, the least integer (N) which is divisible by digit ‘C’ i.e. (1 to 9) must be L.C.M of {1, 3, 4, 6, 7, 9}. = L.C.M of {4, 7, 9} = 252 = N and sum of digits of number ‘N’ is 2+5+2 = 9 |
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