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Let N be the set of natural numbers and for `a in N`, aN denotes the set `{ax : x in N}`. If `bNnncN=dN`, where b, c, d are natural numbers greater than 1 and the greatest common divisor (GCD) of b and c is 1, then d equalsA. `b + c`B. `{b c}`C. `min {b, c}`D. bc |
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Answer» Correct Answer - D We have, `aN={ax : x in N}` = Set of all multiples of a Now, `bN nn cN` - Set of multiples of b and c both `therefore bN nn cN = dN` implies d is a multiple of both b and c implies d=bc `" "[because " GCD of b and c is 1"]` |
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