InterviewSolution
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Let R be a relation on the set A of ordered pair of integers defined by (x, y) R (u, v) if xv = yu. Show that R is an equivalence relation. |
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Answer» First let R be a relation on A Given as set A of ordered pair of integers defined by (x, y) R (u, v) if xv = yu Let us check whether the given relation is equivalence or not. To prove equivalence relation, the given relation should be reflexive, symmetric and transitive. Reflexivity: Let (a, b) be an arbitrary element of the set A. Then, (a, b) ∈ A ⇒ ab = ba ⇒ (a, b) R (a, b) So, R is reflexive on A. Symmetry: Let (x, y) and (u, v) ∈ A such that (x, y) R (u, v). Then, xv = yu ⇒ vx = uy ⇒ uy = vx ⇒ (u, v) R (x, y) Thus, R is symmetric on A. Transitivity: Let (x, y), (u, v) and (p, q) ∈ R such that (x, y) R (u, v) and (u, v) R (p, q) ⇒ xv = yu and uq = vp By, multiplying the corresponding sides, we get xv × uq = yu × vp ⇒ xq = yp ⇒ (x, y) R (p, q) So, R is transitive on A. ∴ R is reflexive, symmetric and transitive. Hence, R is an equivalence relation on A. |
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