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Let the source propagate a sound waves whose intensity ata point (initially) be l. suppose we consider a case when the amplitude of the sound wave is doubled and the frequency is reduced to one-fourth. Calculate now the new intensity of sound at the same point? |
Answer» <html><body><p></p>Solution :Intensity of sound <a href="https://interviewquestions.tuteehub.com/tag/wave-22399" style="font-weight:bold;" target="_blank" title="Click to know more about WAVE">WAVE</a> (old) = `I_(1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/amplitudeof-2415378" style="font-weight:bold;" target="_blank" title="Click to know more about AMPLITUDEOF">AMPLITUDEOF</a> sound wave `(A_(2)) = 2 A_(1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a> of the sound wave `f_(2) = (1)/(4) f_(1)` <br/> Intensity of sound wave `I_(2) = ?` <br/> `I_(1) <a href="https://interviewquestions.tuteehub.com/tag/prop-607409" style="font-weight:bold;" target="_blank" title="Click to know more about PROP">PROP</a> f_(1)^(2) A_(1)^(2) , I_(2) prop f_(2)^(2) A_(2)^(2)` <br/> `(I_(1))/(I_(2)) = (f_(1)^(2) * A_(1)^(2))/(f_(2)^(2) * A_(2)^(2)) = (f_(1)^(2) A_(1)^(2))/((1)/(16) f_(1)^(2) * 4 A_(1)^(2)) = (16)/(4) = 4` <br/> `I_(2) = (1)/(4) I_(1)`</body></html> | |