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Let the source propagate a sound waves whose intensity ata point (initially) be l. suppose we consider a case when the amplitude of the sound wave is doubled and the frequency is reduced to one-fourth. Calculate now the new intensity of sound at the same point? |
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Answer» Solution :Intensity of sound WAVE (old) = `I_(1)` AMPLITUDEOF sound wave `(A_(2)) = 2 A_(1)` FREQUENCY of the sound wave `f_(2) = (1)/(4) f_(1)` Intensity of sound wave `I_(2) = ?` `I_(1) PROP f_(1)^(2) A_(1)^(2) , I_(2) prop f_(2)^(2) A_(2)^(2)` `(I_(1))/(I_(2)) = (f_(1)^(2) * A_(1)^(2))/(f_(2)^(2) * A_(2)^(2)) = (f_(1)^(2) A_(1)^(2))/((1)/(16) f_(1)^(2) * 4 A_(1)^(2)) = (16)/(4) = 4` `I_(2) = (1)/(4) I_(1)` |
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