1.

Let u, v and w be such that |u|=1, |v|=2, |w|=3 If the projection v along u is equal to that of w along u and v, w are perpendicular to each other, then |u-v+w| is equal to

Answer»

2
`SQRT7`
`sqrt(14)`
14

Solution :SINCE, `|u| = 1, |v| = 2,|w| = 3`
The projectionof v ALONG `u = (v.u)/(|u|)` and theprojectionof w along `u = (w.u)/(|u|)`.
ACCORDINGTO givencondition.
`(v.u)/(|u|) = (w.u)/(|u|)`
`rArr v.u = w.u "…."(i)`
Since, v and w are perpendicularto each other.
`:. v. w = 0`
Now, `| u- v + w|^(2) = |u|^(2) +|v|^(2) +|w|^(2)`
`- 2u . v - 2v.w+2u.w`
`rArr |u- b- v + w|^(2) = 1 + 4+ 9 - 2 u . v + 0 + 2u . v` [from EQ. (i) ]
`rArr |u - v + w|^(2) = 1 + 4 + 9`
`:. |u- v + w| = sqrt(14)`


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