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Let y=1/(1+x^(2)) at t=0 s be the amplitude of the wave propogating in the positive x-direction. At t=2 s, the amplitude of the wave propogating becomes y=1/(1+(x-2)^(2)). Assume that the shape of the wave does not change during propogation. The velocity of the wave is |
Answer» <html><body><p>`0.5 ms^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`1.0 ms^(-1)`<br/>`1.5 ms^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.0 ms^(-1)`</p>Solution :`1.0 ms^(-1)` <br/> The general <a href="https://interviewquestions.tuteehub.com/tag/expression-980856" style="font-weight:bold;" target="_blank" title="Click to know more about EXPRESSION">EXPRESSION</a> y in terms of x <br/> `y = (1)/(1 + (x - vt)^(2))` <br/> The shape of the wave does not change: <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> wave move in 2 <a href="https://interviewquestions.tuteehub.com/tag/sec-1197209" style="font-weight:bold;" target="_blank" title="Click to know more about SEC">SEC</a>, 2m in positive .x. direction. So, wave moves 2m in 2 sec.<br/> `therefore`The velocity of the wave =`("displacement")/("time") = (2)/(2) : v = 1 ms^(-1)`</body></html> | |