InterviewSolution
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LetI1 = \(\int_e^{e^2} \cfrac{dx}{log\,x}\) and I2 = \(\int_1^2 \cfrac{e^x}{x}.dx,\) I1 = ∫ dx/log x , x ∈ [e, e2] and I2 = ∫ ex/x .dx, x ∈ [1, 2] then(a) I1 = 1/3 I2 (b) I1 + I2 = 0(c) I1 = 2I2 (d) I1 = I2 |
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Answer» Correct option is: (d) I1 = I2 |
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