LILIL Dellig Compounded half yearly.10. The population of a place incr

1.	LILIL Dellig Compounded half yearly.10. The population of a place increased to 54,000 in 2003 at a rate of 5% per annum(1) find the population in 2001.(ii) what would be its population in 2005?
Answer» less than 2003 in two years. A(2003)= P(2001)(1+R/100)^n 54000 = P (2001)(1+5/100)² 54000 = P(2001)(1+1/20)² 54000= P(2001)(21/20)² 54000 = P(2001)((21×21)/(20×20)) P(2001)=( 54000×20×20)/21×21 Population in 2001 = 48979.59= 48980(approx) ER. RAVI KUMAR ROY (ii)ATQ, population is increasing. Therefore population in 2005, A(2005)= P(1+R/100)^n = 54000(1+5/100)² = 54000(1+1/20)² = 54000( 21/20)² = 54000(21/20)× (21/20) =( 54000× 441)/ 400 =( 540×441)/4 = 238140/4 = 59535 Population in 2005=59535

LILIL Dellig Compounded half yearly.10. The population of a place increased to 54,000 in 2003 at a rate of 5% per annum(1) find the population in 2001.(ii) what would be its population in 2005?

Answer»

less than 2003 in two years.

A(2003)= P(2001)(1+R/100)^n

54000 = P (2001)(1+5/100)²

54000 = P(2001)(1+1/20)²

54000= P(2001)(21/20)²

54000 = P(2001)((21×21)/(20×20))

P(2001)=( 54000×20×20)/21×21

Population in 2001 = 48979.59= 48980(approx)

ER. RAVI KUMAR ROY

(ii)ATQ, population is increasing. Therefore population in 2005,

A(2005)= P(1+R/100)^n

= 54000(1+5/100)²

= 54000(1+1/20)²

= 54000( 21/20)²

= 54000(21/20)× (21/20)

=( 54000× 441)/ 400

=( 540×441)/4

= 238140/4

= 59535

Population in 2005=59535