InterviewSolution
| 1. |
Mark the tick against the correct answer in the following: Let S be the set of all straight lines in a plane. Let R be a relation on S defined by a R b⇔ a ⊥ b. Then, R is A. reflexive but neither symmetric nor transitive B. symmetric but neither reflexive nor transitive C. transitive but neither reflexive nor symmetric D. an equivalence relation |
|
Answer» Correct Answer is (B) symmetric but neither reflexive nor transitive Given set S = {x, y, z} And R = {(x, y), (y, z), (x, z) , (y, x), (z, y), (z, x)} Formula For a relation R in set A Reflexive The relation is reflexive if (a , a) ∈ R for every a ∈ A Symmetric The relation is Symmetric if (a , b) ∈ R , then (b , a) ∈ R Transitive Relation is Transitive if (a , b) ∈ R & (b , c) ∈ R , then (a , c) ∈ R Equivalence If the relation is reflexive , symmetric and transitive , it is an equivalence relation. Check for reflexive Since , (x,x) ∉ R , (y,y) ∉ R , (z,z) ∉ R Therefore , R is not reflexive ……. (1) Check for symmetric Since , (x,y) ∈ R and (y,x) ∈ R (z,y) ∈ R and (y,z) ∈ R (x,z) ∈ R and (z,x) ∈ R Therefore , R is symmetric ……. (2) Check for transitive Here , (x,y) ∈ R and (y,x) ∈ R but (x,x) ∉ R Therefore , R is not transitive ……. (3) Now , according to the equations (1) , (2) , (3) Correct option will be (B) |
|