InterviewSolution
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InterviewSolution
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Match List-I (complex ions) with List-II (number of unpaired electrons) and select the correct answers using the codes given below lists: `{:(List-I,,,,List-II),((Compl ex ion),,,,(Number of Unpaired El ectrons )),(A.,[CrF_6]^(4-),,1.,On e),(B.,[MnF_6]^(4-),,2.,Two),(C.,[Cr(CN)_6]^(4-),,3.,Three),(D.,[Mn(CN)_6]^(4-),,4.,Four), (,,,5.,Five):}`A. (a) `{:(A,B,C,D,),(4,1,2,5,):}`B. (b) `{:(A,B,C,D,),(2,5,3,1,):}`C. (c) `{:(A,B,C,D,),(4,5,2,1,):}`D. (d) `{:(A,B,C,D,),(2,1,3,5,):}` |
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Answer» Correct Answer - C `{:([CrF_6]^(4-),,n=4,,(3d^4)),([MnF_6]^(4-),,n=5,,(3d^5)),([Cr(CN)_6]^(4-),,n=2,,(3d^4)),([Mn(CN)_6]^(4-),,n=1,,(3d^5)):}` n=number of unpaired electrons and that can be calculated by CFT. |
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